EMF

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Table of Contents

#UCLA #Y1Q3 #Physics1B

EMF


Key Definitions

DC Circuit - with one-directional flow of charge

Electromotive Force (EMF) - the extra force in a battery (usually from chemical energy) required to push

Ideal Battery - a battery with an internal resistance of 0


EMF

Defined as the potential:

\(\varepsilon = \int \vec f_s \cdot d\vec l\)

Where

\(\vec f_s = \frac{\vec F_s}{q} \left [\frac N C\right]\)

Such that $\vec F_s$ is the actual force in EMF

Power in a Battery

Power supplied by a battery is defined as

\(P=IV=I\varepsilon\)

EMF in a Battery

The total force acting on a charge in a battery is defined as:

\(\vec F_{net} = q(\vec E + \vec f_s)\)

EMF in a Circuit

Due to the internal resistivity of a battery, $r$:

\(\varepsilon = I(R+r)\)

Thus,

\(I=\frac{\varepsilon}{R+r}\)

Therefore, can be written as:

\(V_{battery}=IR=\varepsilon-Ir\)

Circuits

Open Circuits

If external is taken to infinity in a circuit, we can use EMF to find:

\(I=0\)

Thus

\(V_{battery}=\varepsilon-0=\varepsilon\)

I.e. a circuit with infinite external resistance causes current to go to 0 which is just like an open circuit, so the of the battery is itself

Short Circuit

If resistance goes to 0, current is described as

\(I_{max}=\frac{\varepsilon}{r}\)

Because internal resistance is small, it is equivalent to the EMF, thus

\(V=\varepsilon-\varepsilon=0\)

This is a shorted circuit, so the power is given as

\(P_{max}=\frac{\epsilon^2}{r}\)